Question #135546

The distance from the point P(1,3,2) to the line through (1,0,0), and (1,2,0) is given by ?


Expert's answer

Let M1(1, 0, 0) and M2(1, 2, 0).

We should find

d=∣PM1→×s→∣∣s→∣d=\frac{|\overrightarrow{PM_1}×\overrightarrow{s}|}{|\overrightarrow{s}|} , where s→=M1M2→={1−1,2−0,0−0}={0,2,0}\overrightarrow{s}=\overrightarrow{M_1M_2}=\{ 1-1, 2-0, 0-0\}=\{ 0, 2, 0\} and PM1→={1−1,0−3,0−2}={0,−3,−2}\overrightarrow{PM_1}=\{ 1-1, 0-3, 0-2\}=\{ 0, -3, -2\} .

PM1→×s→=∣i→j→k→0−3−2020∣=i→(0+4)−j→(0−0)+k→(0−0)=4i→={4,0,0}\overrightarrow{PM_1}×\overrightarrow{s}=\begin{vmatrix} \overrightarrow{i} & \overrightarrow{j}&\overrightarrow{k} \\ 0 & -3&-2\\ 0&2&0 \end{vmatrix}=\overrightarrow{i}(0+4)-\overrightarrow{j}(0-0)+\overrightarrow{k}(0-0)=4\overrightarrow{i}=\{ 4, 0, 0\} .

Then d=42+02+0202+22+02=42=2d=\frac{\sqrt{4^2+0^2+0^2}}{\sqrt{0^2+2^2+0^2}}=\frac{4}{2}=2 .


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