Question #132815

Show that the two spheres x²+y²+z²+6y+2z+8=0 and x²+y²+z²+6x+8y+4z+20=0

 are orthogonal.


1
Expert's answer
2020-09-14T19:16:18-0400

2u1u2+2v1v2+2w1w2=d1+d22*u_1*u_2+2*v_1*v_2+2*w_1*w_2=d_1+d_2 --- it is a orthogonality condition

x2+y2+z2+6y+2z+8=0x^2+y^2+z^2+6*y+2*z+8=0 --- the first sphere

u1=0/2=0u_1 = 0/2 = 0 ; v1=6/2=3v_1 = 6/2 = 3 ; w1=2/2=1w_1 = 2/2 = 1 ; d1=8d_1 = 8

x2+y2+z2+6x+8y+4z+20=0x^2 + y^2+z^2+6*x+8*y+4*z+20 = 0 --- the second sphere

u2=6/2=3u_2 = 6/2 = 3 ; v2=8/2=4v_2 = 8/2 = 4 ; w2=4/2=2w_2 = 4/2 = 2 ; d2=20d_2 = 20

As the first sphere is orthogonal to the second sphere, we must have

203+234+221=8+202*0*3+2*3*4+2*2*1=8+20

24+4=2824+4=28

28=2828=28 - equality is true

so these two spheres are orthogonal



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