"9x^2+4y^2+36x-24y+36=0\\\\\n9(x^2+4x+4)+4(y^2-6y+9)-36=0\\\\\n9(x+2)^2+4(y-3)^2=36\\\\\n\\frac{(y-3)^2}{9}+\\frac{(x-(-2))^2}{4}=1\\\\\na^2=9,\\quad b^2=4,\\quad c^2=a^2-b^2\\\\\na=3,\\quad b=2,\\quad c=\\sqrt{5}\\\\\ny_0=3,\\quad x_0=-2\\Rightarrow M(-2,3);\\\\\nthe \\quad foci \\quad are \\quad the \\quad points: \\quad F_1(-2,3-\\sqrt{5}),\\quad F_2 (-2,3+\\sqrt{5})\\\\\nthe \\quad vertices \\quad are :\\quad V_1(6,-2),\\quad V_2(0,-2)\\\\\nV_3(3,0),\\quad V_4(3,-4);"
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