Answer to Question #1232 in Analytic Geometry for olonade emmanuel

Question

a bucket is 20cm in diameter at the open end, 12cm in diameter at the bottom and 16cm deep. to what depth would the bucket fill a cylindricial tin 28cm in diameter

Answer 1

We have to evaluate the volume of the bucket:
V = 1/3 π H (R² + Rr +r²) = 1/3 π *16 (20² +20*12 +12²) = 13136,0461 cm²
The volume of the cylindricial tin is

V = π R² h = π* 28²*h = 13136,0461;
h = 5.33 cm


Answer: the depth is 5.33 cm.