Question #121223
Show that the point (0,3+√5) lies on the ellipse with foci (2,3) and(-2,3) and semi-major axis 3.
1
Expert's answer
2020-06-10T18:33:36-0400


Solution:

the  ellipse    (xx0)2a2+(yy0)2b2=1;x0=0;y0=3;then(x0)2a2+(y3)2b2=1;c=2;b2=a2c2=5;(x0)29+(y3)25=1;the  point(0;  3+5);(00)29+(3+53)25=1;1=1Answer:the  point  (0,3+5)  lies  on  the  ellipsethe\; ellipse\;\;\frac{(x-x_0)^2}{a^2}+\frac{(y-y_0)^2}{b^2}=1;\\x_0=0;y_{0}=3;then\\\frac{(x-0)^2}{a^2}+\frac{(y-3)^2}{b^2}=1;\\c=2;b^2=a^2-c^2=5;\\\frac{(x-0)^2}{9}+\frac{(y-3)^2}{5}=1;the\; point (0;\;3+√5);\\\frac{(0-0)^2}{9}+\frac{(3+\sqrt5-3)^2}{5}=1;\\1=1\\Answer:\\the\; point\; (0,3+√5)\; lies\; on \;the \;ellipse


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