Since the equation of a line with slope mand passing throw the point(x0,y0)isy−y0=m(x−x0).So, we gety−4=m(x+3)\text{Since the equation of a line with slope }m\\ \text{and passing throw the point}(x_0,y_0) is\\ y-y_0=m(x-x_0). \\ \text{So, we get}\\ y-4=m(x+3)Since the equation of a line with slope mand passing throw the point(x0,y0)isy−y0=m(x−x0).So, we gety−4=m(x+3)
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