The equation of the line with the slope has the form
y=kx+by=kx+by=kx+b
According to the problem, k=tanα=−6,k=\tan\alpha=-6,k=tanα=−6,
then y=−6x+by=-6x+by=−6x+b .
The line goes through the origin O(0,0)O(0,0)O(0,0) , hence
substitute coordinates of the origin into the equation of the line:
0=−6⋅0+b,b=0.0=-6\cdot0+b,\\ b=0.0=−6⋅0+b,b=0.
The equation of the line is
y=−6x,6x+y=0.y=-6x,\\ 6x+y=0.y=−6x,6x+y=0.
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments