The equation of the line with the slope has the form
"y=kx+b"
According to the problem, "k=\\tan\\alpha=-6,"
then "y=-6x+b" .
The line goes through the origin "O(0,0)" , hence
substitute coordinates of the origin into the equation of the line:
"0=-6\\cdot0+b,\\\\\nb=0."
The equation of the line is
"y=-6x,\\\\\n6x+y=0."
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