Question #99231
An object is moving with a uniform acceleration a= 2ms^-2, determine the functions for:
A) velocity v (ms^-1) - given v (0) = 10ms^-1 ?
B) displacement s (m) - given s (0) = 5m ?
C) calculate the values of v and s for:
i) t = 2s
ii) t = 5s
1
Expert's answer
2019-11-26T14:07:12-0500

The equations of motion with constant acceleration are:

v(t)=v0+atv(t) = v_0 + a t, s(t)=s0+v0t+at22s(t) = s_0 + v_0 t + \frac{a t^2}{2}

A) Using the first equation, the velocity function is v(t)=10+2tv(t) = 10 + 2 t.

B) Using the second equation, displacement function is s(t)=5+10t+t2s(t) = 5 +10 t + t^2.

C) v(2)=10ms+2ms22s=14msv(2) = 10 \frac{m}{s} + 2 \frac{m}{s^2}\cdot 2 s = 14 \frac{m}{s} , s(2)=5m+10ms2s+1ms222s2=29ms(2) = 5 m + 10\frac{m}{s} \cdot 2 s + 1 \frac{m}{s^2} \cdot 2^2 s^2 = 29 m.

D) v(5)=10ms+2ms25s=20msv(5) = 10\frac{m}{s} + 2\frac{m}{s^2} \cdot 5 s = 20 \frac{m}{s} , s(5)=5m+10ms5s+1ms252s2=80ms(5) = 5 m + 10\frac{m}{s} \cdot 5 s + 1\frac{m}{s^2} \cdot 5^2 s^2 = 80 m.



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Comments

Assignment Expert
25.11.20, 20:44

Values of v0, a, s0 were described in conditions of the question. In C) you substitute t=2 for v(t)=10+2t and get v(2)=14 m/s, substitute t=2 for s(t)=5+10t+t^2 and get s(2)=29 m. In D) you substitute t=5 for v(t)=10+2t and get v(5)=20 m/s, substitute t=5 for s(t)=5+10t+t^2 and get s(5)=80 m.

Deacon
25.11.20, 13:14

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