The equations of motion with constant acceleration are:
v(t)=v0+at, s(t)=s0+v0t+2at2
A) Using the first equation, the velocity function is v(t)=10+2t.
B) Using the second equation, displacement function is s(t)=5+10t+t2.
C) v(2)=10sm+2s2m⋅2s=14sm , s(2)=5m+10sm⋅2s+1s2m⋅22s2=29m.
D) v(5)=10sm+2s2m⋅5s=20sm , s(5)=5m+10sm⋅5s+1s2m⋅52s2=80m.
Comments
Values of v0, a, s0 were described in conditions of the question. In C) you substitute t=2 for v(t)=10+2t and get v(2)=14 m/s, substitute t=2 for s(t)=5+10t+t^2 and get s(2)=29 m. In D) you substitute t=5 for v(t)=10+2t and get v(5)=20 m/s, substitute t=5 for s(t)=5+10t+t^2 and get s(5)=80 m.
What are the steps taken to get to this answer?