Question #97693

Find the term independent of x in the expansion (4x3 +1/2 x) raised to the power eight


1
Expert's answer
2019-10-31T07:01:46-0400

Let given binomial expansion be (a+b)n(a+b)^n

General term ,Tr+1= nCranrbrT_{r+1}=\ ^{n}C_ra^{n-r}b^r


= 8Cr(4x3)8r(12x)r=\ ^{8}C_r(4x^3)^{8-r}({\frac{1}{2x}})^r

Putting power of x=0x=0

We get,


244r=0orr=624-4r=0\\or\\r=6



So term will be

Tr+1=T7= 8C6(42)(12)6=28×1664T_{r+1}=T_7=\ ^8C_6(4^2)(\frac{1}{2})^6=\frac{28\times16}{64}



=7=7


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