f(t)=250e−ktf(t)=250e^{-kt}f(t)=250e−kt
After 250 min: 16=250e−250k16=250e^{-250k}16=250e−250k
So, k=ln250−ln16250=0.011k=\frac{ln250-ln16}{250}=0.011k=250ln250−ln16=0.011
To find the half life we should solve: 0.5=e−0.011t0.5=e^{-0.011t}0.5=e−0.011t
Thus the half life: t=ln0.5−0.11=63 min.t=\frac{ln0.5}{-0.11}=63 \;min.t=−0.11ln0.5=63min.
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