Answer to Question #97445 in Algebra for Denton keller

Question

Witch quadratic equation has roots 7 and -2/3

Answer 1

To solve the problem I used Vieta's formulas.

The roots r₁ , r₂ of the quadratic polynomial P(x)=ax²+bx+c satisfy r₁+r₂=-(b/a), r₁*r₂=c/a

If a=1, then b= -(r₁+r₂)=-(7-2/3)=-(6+1/3), c=r₁*r₂=7*(-2/3)=-14/3.

Answer: x²-(6+(1/3))x-14/3=0