Answer to Question #96625 in Algebra for krystal

Question

an item has a regular price of $40 at three different stores. each store has a different offer for the item

Answer 1

Regular price of item at all the three stores$=40$

Offer at the first store$=10$ %

Price at the first store$=40-\frac{10}{100}\times 40=36$

Offer at the second store is double of that in the first store, so

Price at the second store$=40-\frac{2\times 10}{100}\times 40=32$

Offer at the third store is $\frac{3}{4}^{th}$ of that in the second store.

Price at the third store$=40-\frac{3 \times 2\times 10}{4\times 100}\times 40=34$

Hence price at the third store is the mean of that in the first and the second store.