Question

give the starting value and constant multiplier for each sequence. then find the 7th term of the sequence. 27,18 ,12,...

Answer 1

Give the starting value and constant multiplier for each sequence. then find the 7th term of the sequence. 27,18 ,12,

**Solution:**

This is geometric progression starting value equal to 27. So constant multiplier q equal to

$$q = \frac {a _ {2}}{a _ {1}} = \frac {1 8}{2 7} = \frac {1}{3}$$

Formulae for the n-th term

$$a _ {n} = a _ {1} q ^ {n - 1}$$

For 7th term of our sequence

$$a _ {7} = 2 7 \left(\frac {1}{3}\right) ^ {6} = \frac {2 7}{7 2 9} = \frac {1}{2 7}$$

**Answer:**

starting value equal to 27;

constant multiplier q equal to $\frac{1}{3}$ ;

7th term of sequence $\frac{1}{27}$ ;