G(t)=At2+Bt+CAt t=0G(t)=20soC=20At t=1G(t)=20.5so20.5=A+B+CorA+B=0.5 ........(1)At t =2G(t)=21so,21=4A+2B+Cor4A+2B=1 ........(2)on taking (1) and (2)2A+2B=1 ..........(3)on subtracting equation (3) from (2) we get2A=0 or A=0putting the value of A in equation (1) we get B=0.5we get,A=0B=0.5C=20sovalue of B equals (b)=0.5
Comments