Question

Find the two x- intercept of \\ (f(x)=x^{2}-3x+2\\)

Answer 1

Solution. For x- intercept of f(x) coordinate y=0 (f(x)=0). Find the solution to the equation

$$x^2-3x+2=0$$ $$D=(-3)^2-4\times1\times2=9-8=1$$

Hence, we have two solutions

$$x_1=\frac {3-\sqrt 1} {2}=1, x_2=\frac {3+\sqrt 1} {2}=2.$$

Therefore get two points

$$(1,0), (2,0).$$

Answer. (1,0), (2,0).