Question

Sub 26
Ques. 25

Solve the equation:

logb (x2 + 7) = 2/3logb 64

Answer 1

Question#9388

Sub 26

Ques. 25

Solve the equation:

$$\log b (x^2 + 7) = \frac{2}{3} \log_b 64$$

Solution:

$$\log_b (x^2 + 7) = \frac{2}{3} \log_b 64,$$ $$\log_b (x^2 + 7) = \log_b (64^{\frac{2}{3}}),$$ $$x^2 + 7 = 16$$ $$x^2 = 9$$ $$x = \pm 3$$

Answer:

There are two decisions: $x1 = 3, x2 = -3$.