Find f(4)f(4)f(4) if f(x)=x2−4x+3f(x)=x^2-4x+3f(x)=x2−4x+3
f(x)=x2−4x+3f(x)=x^2-4x+3f(x)=x2−4x+3
We have to find f(4)
substituting 4 in the place of x in the above equation we get
f(4)=42−4⋅4+3=16−16+3=3f(4)=4^2-4\cdot 4+3=16-16+3=3f(4)=42−4⋅4+3=16−16+3=3
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