Answer to Question #93149 in Algebra for Anna

Question

The rate of ice formation in the freezer, compartment is (2-0.3t) g per min: where t is the time in minutes.If there was an initial 10g of ice in the ice-maker,the mass of ice present 10 minutes is

Answer 1

The mass $m$ of the ice in the freezer is defined by the equation

$$m(t)=m_0 2^{-0.3t}$$

Given that $m_0=10 g, t_1=10 min$

Then

$$m(10)=10\cdot 2^{-0.3\cdot 10}=1.25 g$$

The mass of ice present 10 minutes is $1.25 g.$