"(i)\\;\\;\\frac{x^3+3x^2-x-3}{x+3}=\\frac{x^3+3x^2}{x+3}-\\frac{x+3}{x+3}=x^2-1=(x+1)(x-1)"
So, other two factors: "x+1" and "x-1"
(ii) "(-2)^3+3*(-2)^2-(-2)-3=3."
Remainder is 3.
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