Question

Identify the maximum number of relative extrema g(x)=2/x^2+3

Answer 1

In order to find the extremum of a function, you need to find its derivative.

$$g(x)=\frac{2}{x^2}+3;$$

$$\frac{dg(x)}{dx}=2*x^{(-2-1)}*(-2)+0;$$ $$\frac{dg(x)}{dx}=\frac{-4}{x^3} \neq 0$$

As can be seen, the derivative of the function is not zero for any x

Answer: The function has no extrema.