Question #91209

The profit of a company can be modelled by the polynomial function p(t)= -t^3 +12t^2 -21t +10 , where p is the profit, in thousands of dollars and t is the time, in years. When will the company make their maximum profit of $108000?

Expert's answer

find the critical points of the function p(t):


dp(t)dt=0=−3t2+24t−21\frac {d p(t)} {dt}=0=-3t^2+24t-21t1,2=−24±242−4(−3)(−21)2(−3)t_{1,2}=\frac {-24\pm \sqrt{24^2-4(-3)(-21)}} {2(-3)}t1=1,t2=7t_1=1, \quad t_2=7

second derivative test:

d2p(t)dt2=−6t+24\frac {d^2 p(t)} {dt^2}=-6t+24−6t1+24=18>0→t1=1−minimum-6t_1+24=18>0 \quad \to \quad t_1=1-minimum−6t2+24=−18<0→t2=7−maximum-6t_2+24=-18<0 \quad \to \quad t_2=7-maximum

function value:


p(t2)=−(7)3+12(7)2−21(7)+10=108p(t_2)=-(7)^3+12(7)^2-21(7)+10=108

Answer: the company will make a maximum profit of $108,000 in 7 years


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