Question #91209
The profit of a company can be modelled by the polynomial function p(t)= -t^3 +12t^2 -21t +10 , where p is the profit, in thousands of dollars and t is the time, in years. When will the company make their maximum profit of $108000?
1
Expert's answer
2019-06-28T08:55:43-0400

find the critical points of the function p(t):


dp(t)dt=0=3t2+24t21\frac {d p(t)} {dt}=0=-3t^2+24t-21t1,2=24±2424(3)(21)2(3)t_{1,2}=\frac {-24\pm \sqrt{24^2-4(-3)(-21)}} {2(-3)}t1=1,t2=7t_1=1, \quad t_2=7

second derivative test:

d2p(t)dt2=6t+24\frac {d^2 p(t)} {dt^2}=-6t+246t1+24=18>0t1=1minimum-6t_1+24=18>0 \quad \to \quad t_1=1-minimum6t2+24=18<0t2=7maximum-6t_2+24=-18<0 \quad \to \quad t_2=7-maximum

function value:


p(t2)=(7)3+12(7)221(7)+10=108p(t_2)=-(7)^3+12(7)^2-21(7)+10=108

Answer: the company will make a maximum profit of $108,000 in 7 years


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