Let x be the speed of the passenger train,
then x+8 is the speed of the express train.
Time spent by passenger train was 600/x and time for the express train was 600/(x+8).
600/x−600/(x+8)−2.5=0
(600(x+8)−600x−2.5x(x+8))/(x(x+8))=0
600x+4800−600x−2.5x2−20x=0
−2.5x2−20x+4800=0
x2+8x−1920=0
D=82+4∗1∗1920=64+7680=7744
x1=(−8+88)/2=40
x2=(−8−88)/2=−48
Choose the positive value, hence the speed of the passenger train was 40 km/h.
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