1) Sn=n(2a+(n−1)d)n2. S20=(80+19d)∗202=200.S_n=\frac{n(2a+(n-1)d)n}{2}. \;\;S_{20}=\frac{(80+19d)*20}{2}=200.Sn=2n(2a+(n−1)d)n.S20=2(80+19d)∗20=200.
So, d=20−8019=−6019.d=\frac{20-80}{19}=-\frac{60}{19}.d=1920−80=−1960.
2) S=a1−r=21−1920=40.S=\frac{a}{1-r}=\frac{2}{1-\frac{19}{20}}=40.S=1−ra=1−20192=40.
3) Sn=a(1−rn)1−r.S_n=\frac{a(1-r^n)}{1-r}.Sn=1−ra(1−rn).
S10=5(1−210)1−2=5115.S_{10}=\frac{5(1-2^{10})}{1-2}=5115.S10=1−25(1−210)=5115.
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