Question

(x-h)^2=x^2-8x+14
Find the value of h

Answer 1

$$(x-h)^2=x^2-8x+14$$

$$h^2-2xh+8x-14=0$$

$$h_1=\sqrt{\smash[b]{x^{2}-8x+14}}+x$$ $$h_2=x-\sqrt{\smash[b]{x^{2}-8x+14}}$$