Answer to Question #88467 in Algebra for joc

Question #88467
In lnY = b1+ b2 ln(L) + b3 ln(K), where b2 + b3 = 1, b2 + b3 – 1 = 0.
Defining c = b2 + b3 -1, b2 = c – b3 +1.
how is ln(Y/L) = b1 + c ln(L) + b3 ln(K/L) derived from
ln(Y) = b1 + (c –b3 + 1 ) ln(L) + b3 ln(K),
1
Expert's answer
2019-04-24T09:26:07-0400
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