Question

An mtn cellular phone user notices that her cellular phone accounts for three consecutive months were significantly different .in may her account was one and a half times more than her account in june.her account in july was R50 more thanher account in june.in total she spent R575 in cellular accounts in the 3 months.what was her account for each month?
2.2.the sum of three consecutive odd number is 45 .what are the mumbers?

Answer 1

ANSWER to Question #88096 – Math – Algebra

Question

1. An $m$th cellular phone user notices that her cellular phone accounts for three consecutive months were significantly different. In May her account was one and a half times more than her account in June. Her account in July was R50 more than her account in June. In total she spent R575 in cellular accounts in the 3 months. What was her account for each month?

2. The sum of three consecutive odd number is 45. What are the numbers?

Solution

1. Let her account in June be Rs. x. Then

her account in May = Rs. $(x + 1.5 x) = 2.5 x$,

her account in July = Rs. $(x + 50)$.

Total spending $x + 2.5 x + x + 50 = 575 \Rightarrow 4.5 x = 575 \Rightarrow x = 127.78$ (approx)

Hence May account = 2.5(127.78) = Rs. 319.44

June account = Rs. 127.78

July account = Rs. 177.78

2. Let the numbers be $n, n + 2$ and $n + 4$.

Given $n + n + 2 + n + 4 = 45 \Rightarrow 3n = 45 - 6 = 39 \Rightarrow n = 13$

Hence the three numbers will be 13, 15, 17.

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