Answer to Question #87779 in Algebra for Shivam Nishad

Question

In an exponential decay process given by M=Moe^−kt the original amount Mo has been reduced by a factor 16 in 321 days. How many days did it take to be reduced by a factor of 2? What is the value of k ?

Answer 1

1=16e^(-321k) -> -321k=-ln(16) -> k=ln(16)/321=0.0148.

1=2e^(-0.0148t) -> -ln(2)=-0.0148t -> t=ln(2)/0.0148=46.8 days.