The profit function is linear so it can be written in the form
"P(u)=au+b" (1)
where "P(u)" is the profit depending on number of units "u" , "a" and "b" are parameters that we have to find.
Substituting the condition that the profit made by a company when 60 units of its product is sold is $1600 to (1) we get the equation:
"1600=a\u221760+b" (2)
Substituting the condition that when 150 units of its products are sold, the profit increases to $5200 to (1) we get the equation:
"5200=a\u2217150+b" (3)
Now we can find a and b from the system of equations (2),(3).
Lets subtract (2) from (3):
"5200\u22121600=a\u2217150+b\u2212a\u221760\u2212b;"
"3600=a\u221790;"
3600=a∗90;
"40=a;"
"a=40;"
Substituting "a=40" we can find "b" :
"1600=40\u221760+b;"
"1600=2400+b;"
"\u2212800=b;"
"b=\u2212800;"
Substituting values of "a" and "b" to (1) we will get the function "P(u)=40u\u2212800."
Finally, the equation of the profit function is "P(u)=40u\u2212800", where "u" is number of units.
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