The most appropriate strategy to solve x^2-8x=242 is completing the square.
Given quadratic equation x^2-8x=242
Write equation in the form x^2+2ax+a^2=(a+x)^2
Solve for a,
2ax=-8x then we get the value of a is -4
by adding a^2=(-4)^2 to both the sides of given equation,
then we get x^2-8x+(-4)^2 = 242 +(-4)^2
it implies (x-4)^2 = 258
so x-4 = ±√258
therefore x = √258+4 and x = -√258+4
Hence the two zeros of quadratic equation x^2-8x = 242 are x = √258+4, x = -√258 +4.
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