Question

The length of a rectangular dog run is 4ft more than twice it’s width. Find the dimensions of the run if it’s covers 96 ft ^2.

Answer 1

Answer to Question #84739 – Math – Algebra

Question

The length of a rectangular dog run is 4ft more than twice its width. Find the dimensions of the run if it's covers 96 ft ^2.

Solution

Let x = the width

Let 2x + 4 = the length

A = lw

96 = x(2x + 4)

96 = 2x² + 4x

2x² + 4x - 96 = 0

x² + 2x - 48 = 0

(x - 6)(x + 8) = 0

x - 6 = 0 or x + 8 = 0 x = -8 is rejected because the width should be positive

x = 6 feet is the width;

2(6) + 4 = 16 feet is the length.

Answer: 6 feet and 16 feet.

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