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Answer to Question #84734 in Algebra for Elizabeth Driver
Question #84734
The following proof seems to show that 1=2 explain the error clearly
a=b
a^2=ab
a^2-b^2=ab-b^2
(a-b)(a+b)=b(a-b)
a+b=b
b+b=b
2b=b
2=1
a=b
a^2=ab
a^2-b^2=ab-b^2
(a-b)(a+b)=b(a-b)
a+b=b
b+b=b
2b=b
2=1
Expert's answer
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