Answer to Question #77818 in Algebra for Rachael

Question

Prove algebraically that the straight line with equation x=2y+5 is a tangent to the circle with equation x+2y=5
I've already done this
(2y+5)^2+y^2=5
4y^2+20y+25+y^2=5
5y^2420y+20=0
y^2+4y+4=0
(y+2)^2=0
y+2=0
y=-1
x=2(-2)+5=1
(1,-2)
1=2(-2)+5
(1)^2+(-2)^2)5
Please help because I'm only getting 4/5 for my answer and I'm not sure if I have made some sort of mistake

Answer 1

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