Question #76394

Check whether the function f, defined by :
f (x)= cos 2x + tanx,
is periodic. If so, find its period. If f is not
periodic, define a functioning, such that
f — g is periodic.

Expert's answer

Answer on Question #76394 – Math – Algebra

Question

Check whether the function ff, defined by:

f(x)=cos⁡2x+tan⁡xf(x) = \cos 2x + \tan x,

is periodic. If so, find its period. If ff is not periodic, define a functioning, such that

f−gf - g is periodic.

Solution

Let x=0⇒cos⁡0+tan⁡0=1+0=1x = 0 \Rightarrow \cos 0 + \tan 0 = 1 + 0 = 1. We solve equation


cos⁡2x+tan⁡x=1;1−tan⁡2x1+tan⁡2x+tan⁡x=1;1−tan⁡2x+tan⁡x+tan⁡3x=1+tan⁡2x;\cos 2x + \tan x = 1; \quad \frac{1 - \tan^2 x}{1 + \tan^2 x} + \tan x = 1; \quad 1 - \tan^2 x + \tan x + \tan^3 x = 1 + \tan^2 x;tan⁡x(tan⁡2x−2tan⁡x+1)=0⇒tan⁡x=0,tan⁡x=1\tan x(\tan^2 x - 2\tan x + 1) = 0 \Rightarrow \tan x = 0, \tan x = 1x=0±mπ,x=45∘±mπ,m is integer.x = 0 \pm m\pi, \quad x = 45{}^\circ \pm m\pi, \quad m \text{ is integer}.


So, the period of our function is π\pi. Check it.


f(x+π)=f(x)?f(x + \pi) = f(x)?f(x+π)=cos⁡2(x+π)+tan⁡(x+π)=cos⁡(2x+2π)+tan⁡x=cos⁡2x+tan⁡x=f(x).f(x + \pi) = \cos 2(x + \pi) + \tan(x + \pi) = \cos (2x + 2\pi) + \tan x = \cos 2x + \tan x = f(x).


Thus, the function ff defined by f(x)=cos⁡2x+tan⁡xf(x) = \cos 2x + \tan x is periodic. The period of the function is π\pi.

Answer:

The function ff defined by f(x)=cos⁡2x+tan⁡xf(x) = \cos 2x + \tan x is periodic.

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