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Answer to Question #75673 in Algebra for bryan
Question #75673
1/4 x+ 3/8 y= -1
x+y=0
x+y=0
Expert's answer
x/4 + 3y/8 = -1 -> 3y/8 = -1 - x/4 -> 3y/8 = (-4 - x)/4 -> 4 * 3/y= 8 * (-4 - x)
-> 12y = -32 - 8x -> y = -32/12 - 8x/12 -> y = -8/3 -2x/3;
x+y=0 -> x -8/3 -2x/3 = 0 -> (x - 2x)/3 = 8/3 -> (3x - 2x)/3 = 8/3 -> x/3 = 8/3
-> x = (8*3)/3 -> x=8.
x=-y, x= 8 -> y = -8
Check up: 8 - 8 = 0, 8/4 + (3* -8)/8 = 2 + (-24)/8 = 2 - 3 = -1
-> 12y = -32 - 8x -> y = -32/12 - 8x/12 -> y = -8/3 -2x/3;
x+y=0 -> x -8/3 -2x/3 = 0 -> (x - 2x)/3 = 8/3 -> (3x - 2x)/3 = 8/3 -> x/3 = 8/3
-> x = (8*3)/3 -> x=8.
x=-y, x= 8 -> y = -8
Check up: 8 - 8 = 0, 8/4 + (3* -8)/8 = 2 + (-24)/8 = 2 - 3 = -1
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