Question #75291

A company analyses its profits for four consecutive years, from 2007 – 2010. The profit made in 2007 was twice that in 2009. The profit made in 2008 was R 14 million more than the profit made in 2009, while the profit made in 2010 was R 4 million less than the profit made in 2007. If the total profit made in these four years was R 58 million, determine the profit made in each year. (
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Expert's answer

2018-03-31T09:29:08-0400

Question #75291, Math / Algebra

A company analyses its profits for four consecutive years, from 2007 – 2010. The profit made in 2007 was twice that in 2009. The profit made in 2008 was R 14 million more than the profit made in 2009, while the profit made in 2010 was R 4 million less than the profit made in 2007. If the total profit made in these four years was R 58 million, determine the profit made in each year.

Solution:

Let the profit made in 2008 was R x million. Then the profit made in 2009 was x/2.

The profit made in 2008 was R 14 million more than the profit made in 2009, it means: x/2+Rx / 2 + R 14 million. And the profit made in 2010 was R 4 million less than the profit made in 2007, it means: x-R 4 million. At last, the total profit made in these four years was R 58 million, it means: x+x/2+Rx + x / 2 + R 14 million +x/2+xR+ x / 2 + x - R 4 million =R= R 58 million.

3x+R3x + R 10 million =R= R 58 million;

3x=R3x = R 48 million;

x=Rx = R 16 million;

In this way, the profit made in 2007 was R 16 million, the profit made in 2008 was R 22 million, the profit made in 2009 was R 8 million, and the profit made in 2010 was R 12 million.

Answer:

The profit made in 2007 was R 16 million, the profit made in 2008 was R 22 million, the profit made in 2009 was R 8 million, and the profit made in 2010 was R 12 million.

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