Question #70620

Charlie has 218 fewer Facebook friends than leana. The number of Deepa's Facebook friends is 28 more than half of Ileana's. Together Charlie, Deepa, and Ileana have 2175 friends on Facebook. How many Facebook friends does each of them have?
1

Expert's answer

2017-10-26T14:37:06-0400

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Answer on Question #70620 – Math – Algebra

Question

Charlie has 218 fewer Facebook friends than Ileana. The number of Deepa's Facebook friends is 28 more than half of Ileana's. Together Charlie, Deepa, and Ileana have 2175 friends on Facebook. How many Facebook friends does each of them have?

Solution

Let xx be the number of Charlie's friends, yy be the number of Deep's friends and zz be the number of Ileana's friends.

We form the equation for given conditions.

Together Charlie, Deepa, and Ileana have 2175 friends on Facebook:


x+y+z=2175x + y + z = 2175


The number of Deepa's Facebook friends is 28 more than half of Ileana's.


y=12z+28y = \frac{1}{2}z + 28


Charlie has 218 fewer Facebook friends than Ileana:


x=z218x = z - 218


We have obtained a system of equations in three variables:


{x+y+z=2175y=12z+28x=z218\left\{ \begin{array}{c} x + y + z = 2175 \\ y = \frac{1}{2}z + 28 \\ x = z - 218 \end{array} \right.


We substitute for yy and xx from the equations (2), (3) into the equation (1) and get the following equation:


z218+12z+28+z=217552z190=217552z=2365z=2×23655z=946\begin{array}{l} z - 218 + \frac{1}{2}z + 28 + z = 2175 \\ \frac{5}{2}z - 190 = 2175 \\ \frac{5}{2}z = 2365 \\ z = \frac{2 \times 2365}{5} \\ z = 946 \end{array}


Substituting the value zz from (4) into the equations (2) and (3) we get xx and yy:


{z=946x=728y=501\left\{ \begin{array}{l} z = 946 \\ x = 728 \\ y = 501 \end{array} \right.


Answer: Charlie has 728 friends in Facebook, Deep has 501 friends and Ileana has 946 friends.

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