Question #68167

The formula for final velocity of an object starting from zero and undergoing constant acceleration is v=1/2at^2, what is the time it will take a car accelerating at 4 m/s^2 to reach 50m/s
1

Expert's answer

2017-05-12T13:14:09-0400

Answer on Question #68167 – Math – Algebra

Question

The formula for final velocity of an object starting from zero and undergoing constant acceleration is v=1/2at2v = 1/2at^2, what is the time it will take a car accelerating at 4m/s24 \, \text{m/s}^2 to reach 50m/s50 \, \text{m/s}

Solution

The formula for final velocity of an object starting from zero and undergoing constant acceleration is


v=12at2,v = \frac{1}{2} \cdot a \cdot t^2,


where aa is acceleration, tt is time, vv is velocity.

It follows from this equation that


t2=2va,t^2 = \frac{2v}{a},t=2va.t = \sqrt{\frac{2v}{a}}.


Substitute v=50(m/s)v = 50 \, (\text{m/s}), a=4(m/s2)a = 4 \, (\text{m/s}^2) into the previous formula:


t=2504=25=5(s)t = \sqrt{\frac{2 \cdot 50}{4}} = \sqrt{25} = 5 \, (\text{s})


Answer: It will take 5 seconds.

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