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Answer to Question #67916 in Algebra for Krish
Question #67916
The charge relationship for a capacitor is given by the following expression:
1/2QV = 1/2CV²
Find V if Q = 750x10^-6 colombs and C = 6x10^-6 farads
1/2QV = 1/2CV²
Find V if Q = 750x10^-6 colombs and C = 6x10^-6 farads
Expert's answer
1/2QV=1/2CV^2
QV=CV^2
Q=CV
V=Q/C=(750*10^(-6))/(6*10^(-6))=750/6=125 (volt)
QV=CV^2
Q=CV
V=Q/C=(750*10^(-6))/(6*10^(-6))=750/6=125 (volt)
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