Question #6247

Which expression competes the equation cscθ+1/cotθ to make it an identity?

Expert's answer

Problem #6168 Complete the equation csc(θ)+1/cot(θ)=csc(\theta) + 1 / cot(\theta) = \ldots

Solution There can be various solutions. One of them is cscθ+1/cotθ=1sinθ+sinθcosθ=cosθ+sin2θsinθcosθ=(cotθ+sinθ)1cosθ=(cotθ+1/cscθ)secθcsc\theta + 1 / cot\theta = \frac{1}{\sin\theta} + \frac{\sin\theta}{\cos\theta} = \frac{\cos\theta + \sin^2\theta}{\sin\theta\cos\theta} = (\cot\theta + \sin\theta)\frac{1}{\cos\theta} = (\cot\theta + 1 / csc\theta) \cdot sec\theta.

Answer csc(θ)+1/cot(θ)=(cotθ+1/cscθ)secθcsc(\theta) + 1 / cot(\theta) = (\cot \theta + 1 / csc\theta) \cdot sec\theta.

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