Question #56379

18: Assume f(x) = -2x + 8 and g(x) = 3x , what is the value of (g o f)(3)?

A: 6
B: x + 8
C: -10
D: 23

19: None

20: Let h(x) = (g o f)(x) = x^2/ x^2 + 1
Which of the following could be a possible decomposition of h(x)?

A: F(x) = x^2 ; g(x) = x
-------
x + 1

B: f(x) = x + 1; g(x) = x^2

C: f(x) = x + 1; g(x) = 1
-----
x^2

D: f(x) = x ;g(x) = x
-------
x + 1

Expert's answer

QUESTION №18

Assume f(x)=2x+8f(x)=-2x+8 and g(x)=3xg(x)=3x, what is the value of (gof)(3)(gof)(3) ?

A:A: 66

B:B: x+8x+8

C:C: 10-10

D:D: 2323

SOLUTION

(gof)(x)=g(f(x))=g(2x+8)=3(2x+8)=6x+24(gof)(x)=g\left(f(x)\right)=g(-2x+8)=3(-2x+8)=-6x+24

(gof)(3)=(6x+24)x=3=2463=2418=6(gof)(3)=\left.(-6x+24)\right|_{x=3}=24-6*3=24-18=6

ANSWER

(gof)(3)=6(gof)(3)=6

A:6

QUESTION №20

Let h(x)=(gof)(x)=x2x2+1h(x)=(gof)(x)=\frac{x^{2}}{x^{2}+1}

Which of the following could be a possible decomposition of h(x)h(x)?

A:A: f(x)=x2; g(x)=xx+1f(x)=x^{2};\ g(x)=\frac{x}{x+1}

B:B: f(x)=x+1; g(x)=x2f(x)=x+1;\ g(x)=x^{2}

C:C: f(x)=x+1; g(x)=1x2f(x)=x+1;\ g(x)=\frac{1}{x^{2}}

D:D: f(x)=x; g(x)=xx+1f(x)=x;\ g(x)=\frac{x}{x+1}

SOLUTION

h(x)=(gof)(x)=g(f(x))=x2x2+1h(x)=(gof)(x)=g\left(f(x)\right)=\frac{x^{2}}{x^{2}+1}

Iterate through all the options one by one

A:A: f(x)=x2; g(x)=xx+1f(x)=x^{2};\ g(x)=\frac{x}{x+1}

h(x)=g(f(x))=g(x2)=x2x2+1h(x)=g(f(x))=g(x^{2})=\frac{x^{2}}{x^{2}+1}

B:f(x)=x+1;  g(x)=x2B: \quad f(x) = x + 1; \; g(x) = x^2h(x)=g(f(x))=g(x+1)=(x+1)2h(x) = g(f(x)) = g(x + 1) = (x + 1)^2C:f(x)=x+1;  g(x)=1x2C: \quad f(x) = x + 1; \; g(x) = \frac{1}{x^2}h(x)=g(f(x))=g(x+1)=1(x+1)2h(x) = g(f(x)) = g(x + 1) = \frac{1}{(x + 1)^2}D:f(x)=x;  g(x)=xx+1D: \quad f(x) = x; \; g(x) = \frac{x}{x + 1}h(x)=g(f(x))=g(x)=xx+1h(x) = g(f(x)) = g(x) = \frac{x}{x + 1}


ANSWER


A:f(x)=x2;  g(x)=xx+1A: \quad f(x) = x^2; \; g(x) = \frac{x}{x + 1}


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