Question #54913

Consider the following quadratic function.
f(x) = x2 − 6x − 7

Find the x- and y-intercepts of the graph, if any exist. (If an answer does not exist, enter DNE.)
x-intercept (x, y) = (larger x value)
x-intercept (x,y)= (smaller x value)

Convert the function into standard form.
f(x) =

Graph the quadratic function.


Identify the vertex and the axis of symmetry.
vertex
(x, y) =



axis of symmetry
1

Expert's answer

2015-09-24T12:01:22-0400

Answer on Question #54913 - Math - Algebra

Consider the following quadratic function.


f(x)=x26x7f (x) = x ^ {2} - 6 x - 7


Find the x- and y-intercepts of the graph, if any exist. (If an answer does not exist, enter DNE.)

x-intercept (x,y)=(x,y) = (larger x value)

x-intercept (x,y)=(x,y) = (smaller x value)

Convert the function into standard form.


f(x)=f (x) =


Graph the quadratic function.

Identify the vertex and the axis of symmetry.

vertex


(x,y)=(x, y) =

Solution

Find the xx - and yy -intercepts of the graph, if any exist. (If an answer does not exist, enter DNE.)


x26x7=0D=624(7)=82x1=682=1,x2=6+82=7x ^ {2} - 6 x - 7 = 0 \rightarrow | D = 6 ^ {2} - 4 \cdot (- 7) = 8 ^ {2} | \rightarrow x _ {1} = \frac {6 - 8}{2} = - 1, x _ {2} = \frac {6 + 8}{2} = 7f(0)=02607=7f (0) = 0 ^ {2} - 6 \cdot 0 - 7 = - 7


Thus,


yintercept is(x,y)=(0;7)y - \text {intercept is} (x, y) = (0; - 7)xintercept(x,y)=(largerx value)=1x - \text {intercept} (x, y) = (\text {larger} x \text { value}) = - 1xintercept(x,y)=(smallerx value)=7x - \text {intercept} (x, y) = (\text {smaller} x \text { value}) = 7


Convert the function into standard form.


f(x)=x26x+99+7=(x3)22f (x) = x ^ {2} - 6 x + 9 - 9 + 7 = (x - 3) ^ {2} - 2


Graph the quadratic function.



Identify the vertex and the axis of symmetry.

vertex is


(x,y)=(3;2)(x, y) = (3; - 2)


axis of symmetry is


x=3x = 3


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