Answer on Question #54913 - Math - Algebra
Consider the following quadratic function.
f(x)=x2−6x−7
Find the x- and y-intercepts of the graph, if any exist. (If an answer does not exist, enter DNE.)
x-intercept (x,y)= (larger x value)
x-intercept (x,y)= (smaller x value)
Convert the function into standard form.
f(x)=
Graph the quadratic function.
Identify the vertex and the axis of symmetry.
vertex
(x,y)=Solution
Find the x - and y -intercepts of the graph, if any exist. (If an answer does not exist, enter DNE.)
x2−6x−7=0→∣D=62−4⋅(−7)=82∣→x1=26−8=−1,x2=26+8=7f(0)=02−6⋅0−7=−7
Thus,
y−intercept is(x,y)=(0;−7)x−intercept(x,y)=(largerx value)=−1x−intercept(x,y)=(smallerx value)=7
Convert the function into standard form.
f(x)=x2−6x+9−9+7=(x−3)2−2
Graph the quadratic function.

Identify the vertex and the axis of symmetry.
vertex is
(x,y)=(3;−2)
axis of symmetry is
x=3
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