Question

prove that for n there exists a natural number, (2n/n)+(2n/n+1)=1/2((2n+2)/(n+1))

Answer 1

n<>0
n<>-1
2(2n(n+1)+2n(n+1)+n(n+1))/(n(n+1))-2n(n+1)/(n(n+1))=0
8n(n+1)/(n(n+1)=0
8=0
4=-4
for n, there exists a positive integer