Answer to Question #50626 in Algebra for Lee

Question

Two trains started from the same station at the same time and traveled in opposite directions. One train's speed was 12 faster than the other. In 5 hours, they were 532 km apart. Find the rate of the faster train. Round-off your answer to one decimal place.

Answer 1

Answer:
Let x is one train's speed, than other train's speed will be x+12. So, their overall rate we can write as x+(x+12).
We know, that trains started from the same station at the same time and in 5 hours, they were 532 km apart. Write equation of their movement according this information:
(x+(x+12))*5=532
(2x+12)*5=532
10x=532-60
10x=472
x=47,2 km/h - rate of the slower train.
47,2+12=59,2 km/h - rate of the faster train.