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Answer to Question #4925 in Algebra for jojo alex
Question #4925
the sum of 2 numbers is 16 the sum of their reciprocals is 1/3 find the number ?
Expert's answer
Solution
We have two unknown numbers and two conditions on these numbers.
Let's designate these numbers through x , y.
Let's make system of the equations.
Let's solve system of the equations.
=> 
Thus
or 
Answer: These numbers are 4 and 12.
We have two unknown numbers and two conditions on these numbers.
Let's designate these numbers through x , y.
Let's make system of the equations.
Let's solve system of the equations.
=> Thus
or Answer: These numbers are 4 and 12.
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Comments
a+b=16 1/a+1/b=1/3 ab=48 a*(16-a)=48 a2-16a+48=0 a2-12a-4a+48=0 a(a-12)-4(a-12)=0 a=4,12
the numbers are following 1st number = 4 2nd number = 12
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