Answer on Question #44572 - Math - Algebra
Show that if y=?(1−x)z, then 1−y=(1−x)(1−z)+x.
Solution.
If y=(1−x)z⇒−y=−(1−x)z⇒1−y=−(1−x)z+1=−(1−x)(z−1+1)+1=−(1−x)(z−1)−(1−x)+1=−(1−x)(z−1)−1+x+1=(1−x)(1−z)+x.
Answer: if y=(1−x)z, then 1−y=(1−x)(1−z)+x.
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