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Answer to Question #4413 in Algebra for zm
Question #4413
make y the subject.
x=2/3y^2+4
x=2/3y^2+4
Expert's answer
Let's subtract 4 from each part of equation:
x-4 = 2/3y^2
Trransfering the multiplier:
3/2(x-4) = y^2
So, y = (3/2(x-4))^0.5
x-4 = 2/3y^2
Trransfering the multiplier:
3/2(x-4) = y^2
So, y = (3/2(x-4))^0.5
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