Answer to Question #3661 in Algebra for tami

Question #3661
Solve 2e[sup]2x[/sup] + 19e[sup]x[/sup]-27=0.
Moderate step by step would be great! Thanks!
1
Expert's answer
2011-07-19T11:43:40-0400
Denote ex as t, thus the equation is
2t2 +19t -27 = 0
D = 192 + 4*2*27 = 577
t1 = (-19 + √577)/4
t2 = (-19 - √577)/4 < 0 - doesnt's satisfy the conditions, as ex >=0 at any x.

ex = (-19 + √577)/4, x = ln(-19 + √577) - ln4

Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!

Leave a comment

LATEST TUTORIALS
New on Blog
APPROVED BY CLIENTS