2900 dollars is placed in an account with an annual interest rate of 9%. How much will be in the account after 13 years, to the nearest cent?
For this case we assume that we can use the compound interest formula given by:
"A=P(1+\\frac {r}{n}) ^{nt}"
Where:
A =the future value;
P =the present value;
r = the interest rate on fraction;
n =number of times that the interest is effective in a year.
For this case we have the following info:
P = 2900$
r = 0.09
n = 1 (since it's annual)
t = 13 year
We want to find the value of of A and if we replace we got:
"A= 2900*(1+\\frac {0.09}{1}) ^{1*13}= 8890.83"
And the value after 13 years would be $8890.83
And the amount of interest earned would be:
8890.83 - 2900 = $5990.83
Answer: The value after 13 years would be $8890.83.
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