Question #348842

Tell whether if the following piecewise function is a continuous at a given point or not. (SHOW THE SOLUTION).



2. at x = 0



1/x if x ≤ -1


x² - 2 if x > -1




1
Expert's answer
2022-06-09T06:14:17-0400

f(x)f(x) is continuous at a point x=ax=a if f(a)f(a) is defined and limxaf(x)=f(a).lim_{x\to a} f(x)=f(a).

The function

f(x)={1x,if x1,x22,if x>1,f(x)=\{\begin{matrix} \frac{1}{x}, & \text{if }x\leq-1, \\ x^2-2, & \text{if }x>-1, \end{matrix}

is defined at x=0:x=0:

f(0)=022=2.f(0)=0^2-2=-2.


limx0f(x)=limx0(x22)=022=2,lim_{x\to 0^-} f(x)=lim_{x\to 0^-} (x^2-2)=0^2-2=-2,


limx0+f(x)=limx0+(x22)=022=2=limx0f(x),lim_{x\to 0^+} f(x)=lim_{x\to 0^+} (x^2-2)=0^2-2=-2=lim_{x\to 0^-} f(x),


so there exist limx0f(x)=2=f(0)lim_{x\to 0} f(x)=-2=f(0) and the function is continuous at x=0.x=0.


We can see the continuity at x=0x=0 at the graph of f(x)f(x) :




Answer: the function is continuous at x=0.


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