Tell whether if the following piecewise function is a continuous at a given point or not. (SHOW THE SOLUTION).
2. at x = 0
1/x if x ≤ -1
x² - 2 if x > -1
"f(x)" is continuous at a point "x=a" if "f(a)" is defined and "lim_{x\\to a} f(x)=f(a)."
The function
"f(x)=\\{\\begin{matrix}\n \\frac{1}{x}, & \\text{if }x\\leq-1, \\\\\n x^2-2, & \\text{if }x>-1,\n\\end{matrix}"
is defined at "x=0:"
"f(0)=0^2-2=-2."
"lim_{x\\to 0^-} f(x)=lim_{x\\to 0^-} (x^2-2)=0^2-2=-2,"
"lim_{x\\to 0^+} f(x)=lim_{x\\to 0^+} (x^2-2)=0^2-2=-2=lim_{x\\to 0^-} f(x),"
so there exist "lim_{x\\to 0} f(x)=-2=f(0)" and the function is continuous at "x=0."
We can see the continuity at "x=0" at the graph of "f(x)" :
Answer: the function is continuous at x=0.
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