Show that if 5/3< 2x< 11/3, then x∈{y∈R such that |y- 4/3| < 1/2}
"\\dfrac{5}{6}<x<\\dfrac{11}{6}"
"\\dfrac{5}{6}-\\dfrac{4}{3}<x-\\dfrac{4}{3}<\\dfrac{11}{6}-\\dfrac{4}{3}"
"-\\dfrac{1}{2}<x-\\dfrac{4}{3}<\\dfrac{1}{2}"
Therefore if "\\dfrac{5}{3}<2x<\\dfrac{11}{3}," then "|x-\\dfrac{4}{3}|<\\dfrac{1}{2}."
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